solve for x: log6(x+29) - log6(x-6) = 2

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02-06-2015
Mathematics

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solve for x: log6(x+29) - log6(x-6) = 2

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darth666 darth666 · Answer 1 · 2015-06-02T23:03:31+02:00

darth666 darth666

02-06-2015

[tex]log_6(x+29)-log_6(x-6)=2[/tex]
[tex]log_6{6^2}=2[/tex]
[tex]log_6(x+29)-log_6(x-6)=log_6{6^2}=log_6{36}[/tex]
[tex]log_6(x+29)-log_6(x-6)=\frac{log_6(x+29)}{log_6(x-6)}=log_6{36}[/tex]
[tex]\frac{x+29}{x-6}=36[/tex]
[tex]x+29=36(x-6)[/tex]
[tex]x+29=36x-216[/tex]
[tex]35x=245[/tex]
[tex]x=\frac{245}{35}=7[/tex]
[tex]log_6{36}-log_6{1}=2[/tex]

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