reganlynn33
reganlynn33 reganlynn33
  • 01-06-2017
  • Chemistry
contestada

If you start witg 14.8g of C3H8 and 3.44g of O2, determine the limiting reagent

Respuesta :

fatouramjaun
fatouramjaun fatouramjaun
  • 01-06-2017
firstly write down the equation:

C3H8 + 5O2 = 3CO2 + 4H20


THEN Calculate the number of mole of each of them
ME OF C3H8 =44
n(C3H8) = (14.8) / 44 =0.336
n(O2) =x (calculate it )

do the same for oxygen then
followed by that

use mole ratio 1 mole of C3H8 react with 5 mole of O2,

BUT  YOU USE ONLY x MOLE OF O2\

if u still have any problem please feel free...
Answer Link

Otras preguntas

if the area of circular pond is 154 π square meter, find the radius of it's base ​
Contrast overloading to overtraining. What is one difference between these two concepts? A. Overloading is spontaneous; overtraining is carefully planned. B.
Which system of inequalities represents the graph
An electron moved from a higher energy level to a lower energy level. What most likely happened during the transition? A photon was released. A photon was abso
Solve the equation X+3y=13 X^2+3y^2=43
A box has 16 candies.12 red and 4 yellow.If you were picking candies from the box without looking.How many candies would you hav to pick up to be certain to fin
this figure has rotational symmetry. what is true about the figure?
PLSSSS HLEP What Number should go in the empty boxes to complete the calculation for 0.35 x 0.67
PLEASE HELP WILL GIVE BRAINLIEST AND 5.0 RATING
Select the correct answer. Is the boxed word a SUBJECT or a VERB? Will we need our driver's licenses for the application? OA. Subject OB. Verb