gsom gsom
  • 04-04-2015
  • Mathematics
contestada

how do I solve for x in x^2 - 8x + 12 = 0 using factoring?

Respuesta :

konrad509
konrad509 konrad509
  • 04-04-2015
[tex] x^2 - 8x + 12 = 0\\ x^2-2x-6x+12=0\\ x(x-2)-6(x-2)=0\\ (x-6)(x-2)=0\\ x=6 \vee x=2[/tex]
Answer Link
0000000
0000000 0000000
  • 04-04-2015
[tex]\rm x^2-8x+12=0 \\ \\ x^2-2x-6x+12=0 \\ \\ x(x-2)-6(x-2)=0 \\ \\ (x-2)(x-6)=0 \\ \\ \bold{I:x-2=0 \longrightarrow x=2} \\ \bold{II:x-6=0 \longrightarrow x=6}[/tex]
Answer Link

Otras preguntas

56 out of 128 students went on a trip during vacations what percent of students went on trips
what I saw in the closet left me speechless. a.) direct object b.) predictive nominative c.) subject d.) object of a preposition
1. Which one of the following items would be most likely to have a list of chapter titles? A. A novel B. A magazine C. An article D. A newspaper
What is the mass in grams of 1.73 moles CaH2
15% of what number is 12
what is a "summary number model"?
what is the gcf of 86,129,and 215
Why were Americans encouraged to grow their own food in victory gardens? To increase the amount of food that could be sold to other nations. To conserve resourc
Have have the oceans and seas surrounding North Africa and Southwest Asia benefited the region?
What changes to landforms can ice cause?