Respuesta :

FadaKen

[tex] \frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C} [/tex]for any triangle:


BasketballEinstein

Solving for Angles

[tex]\displaystyle \frac{sin∠C}{c} = \frac{sin∠B}{b} = \frac{sin∠A}{a}[/tex]

Make sure to use [tex]\displaystyle sin^{-1}[/tex]towards the end, or elce you will throw your answer off!

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Solving for Edges

[tex]\displaystyle \frac{c}{sin∠C} = \frac{b}{sin∠B} = \frac{a}{sin∠A}[/tex]

I am joyous to assist you at any time.