Awesomemathman Awesomemathman
  • 01-03-2017
  • Mathematics
contestada


A right triangle has one leg that is 13 cm long. The hypotenuse is 27 cm long l. Find the area of the triangle to the nearest tenth .

Respuesta :

Livingsta
Livingsta Livingsta
  • 07-03-2017
For a right angle triangle,

Hypotenuse² = base² + height² 
Hypotenuse = 27 cm
One leg (x) = 13 cm(could be either base or height)
Let other leg be y

Hypotenuse² = x² + y²

27² = 13² + y²
y² = 27² - 13² = 729 - 169 = 560 = 23.66cm

Area of triangle = 1/2 bh = 1/2 x 13 x 23.66 = 153.79 cm²
Answer Link

Otras preguntas

¿Dónde están mis 10 errores? Find 10 errors in the following text. "Hola. Me llamo es Kimberly. Soy muy alto y amable. Me gusta mucho los deportes, especialment
A 0.5kg football thrown by Tony Romo with a velocity of 15 m/s is caught by a stationary receiver and brought to rest in 0.02 seconds. a) what impulse is delive
what is the product? 1/2*[12,64 -78,30]
Define allusion in your own words. Also, give a example of allusion.
George walked on a treadmill 16 ¾ miles over 4 days. How many miles did he walk per day?
what does one and sixty-three hundredths look like?
What is sectionalism
Which two things do all plants need for photosynthesis? * Carbon dioxide and soil Water and carbon dioxide Insects and water Soil and sugar .
Consider the following code segment. int[][] arr = {{3, 2, 1}, {4, 3, 5}}; for (int row = 0; row < arr.length; row++) { for (int col = 0; col < arr[row].l
What value of x satisfies the conclusion of the mean value theorem for f(x) = ln(x3) over the interval [1, e2]?