FannieK727258 FannieK727258

03-11-2022
Mathematics

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please answer quickly I'm just trying to confirm my answer

please answer quickly Im just trying to confirm my answer class=

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RaphealW453149 RaphealW453149

03-11-2022

Given the following vector:

[tex]v=<-\sqrt{3},2\sqrt{3}>[/tex]

The magnitude of the vector will be as follows:

[tex]||v||=\sqrt{(-\sqrt{3})^2+(2\sqrt{3})^2}=\sqrt{3+12}=\sqrt{15}[/tex]

So, the answer will be option 2) ||v|| = √15

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