Answer:
[tex]\huge\boxed{\sf x =5 \ \ \ OR \ \ \ x = 1}[/tex]
Step-by-step explanation:
Given equation:
[tex]x^2-6x+5=0[/tex]
Using mid-term break formula
- Multiply -5 and -1 gives +5 (side term) and adding them gives -6 (mid term).
- So, split -6 into -5 and -1
[tex]x^2-5x-x+5=0\\\\Take \ common\\\\x(x-5)-1(x-5)=0\\\\Take \ (x-5) \ common\\\\(x-5)(x-1)=0[/tex]
Either,
x - 5 = 0 OR x - 1 = 0
x = 5 OR x = 1
[tex]\rule[225]{225}{2}[/tex]
