lisbethmariagonz03 lisbethmariagonz03

04-01-2022
Mathematics

contestada

There are 13 cards of each suit in a deck of 52 cards (13 hearts, 13 diamonds, etc.). What is the probability of
not picking a diamond? Simplify, if possible.

Respuesta :

renknee renknee

04-01-2022

Answer:

3/4

Step-by-step explanation:

1. Since we know there are 13 diamonds in the card deck containing 52 cards, we first subtract 13 from 52.

[tex]52 - 13 = 39[/tex]

2. Now, because there's still 52 cards in total but only 39 are not diamonds, the probability of not getting a diamond card is 39/52. However, 39/52 have a common factor of 13. 39/13 = 3, and 52/13 = 4. Therefore, the simplified probability is 3/4.

Answer Link

Otras preguntas

The narrator often issues disclaimers by saying “people said” or “it is said.” how do you respond to these disclaimers? how do you think other readers might res

The time to fly between new york city and chicago is uniformly distributed with a minimum of 120 minutes and a maximum of 150 minutes. what is the probability t

your new pet kitten is trapped in a ten foot deep hole. you need a contraption to safely rescue your poor animal. I am supposed to use the engineering design p

in a court trial who tries to prove with facts and witnesses that the defendant is guilty of the crime?

During the Mississippian period, many Native Americans set up large fields where they primarily grew: Question 2 options:

Research and find one major primary document from the Civil War. Either copy and paste into a document from the internet, or scan or photocopy it if you are usi

Select all that apply. Pathogens include:

Which mathematical term cannot be defined for all cases in a system of geometry?

Given a normal market demand curve for leather wallets and purses, if people find that backpacks are a better option, then there is an increase in demand for le

As part of the patient self-determination act of 1990, patients have the right accurate and easy-to-understand information about their medical condition. this i