yaredgenanaw99 yaredgenanaw99

02-10-2021
Mathematics

contestada

principal argument for (√3-i)^6

Respuesta :

lujain792003 lujain792003

02-10-2021

Answer:

r= [tex]\sqrt{(\sqrt{3})^{6} +(1)^{2} } =\sqrt{4} =2[/tex]

(2)^5(cos(330.6)+isin(330.6))

=64(Cos1350+iSin1350)

64(cos180+isin180)

=64(-1+0)= -64

Step-by-step explanation:

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