Respuesta :

sqdancefan

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Answer:

  • a = 3
  • b = -18

Step-by-step explanation:

Using the least common denominator, we have ...

  [tex]2-\dfrac{x+1}{x-2}-\dfrac{x-4}{x+2}\\\\=\dfrac{2(x-2)(x+2)-(x+1)(x+2)-(x-4)(x-2)}{(x-2)(x+2)}\\\\=\dfrac{2(x^2-4)-(x^2+3x+2)-(x^2-6x+8)}{x^2-4}\\\\=\dfrac{(2-1-1)x^2+(-3+6)x+(-8-2-8)}{x^2-4}=\boxed{\dfrac{3x-18}{x^2-4}}[/tex]

The values of a and b are ...

  a = 3

  b = -18