Seudónimo Seudónimo
  • 02-07-2020
  • Mathematics
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Please help urgently!

Please help urgently class=

Respuesta :

Plus16463574585
Plus16463574585 Plus16463574585
  • 02-07-2020

Answer:

[tex]a=-6\quad and \quad b=8[/tex]

Step-by-step explanation:

[tex]\frac{8-\sqrt{18}}{\sqrt{2}}=\frac{\sqrt{2}}{\sqrt{2}}\times \frac{8-\sqrt{18}}{\sqrt{2}}\\\\=8\sqrt{2}-\sqrt{2}\cdot \sqrt{18}\\\\=8\sqrt{2}-\sqrt{36}\\\\=-6+8\sqrt2[/tex]

By comparing the last expression with  [tex]a+b\sqrt{2}[/tex], we get:

[tex]a=-6\quad and \quad b=8[/tex]

Best Regards!

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jahshauushshaha
jahshauushshaha jahshauushshaha
  • 02-07-2020
For a: a = 4√2 - 3 - b √2

For b: b = ( 4√2 - 3 - a )√ 2 / 2
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