zayo679 zayo679
  • 01-07-2020
  • Mathematics
contestada

Solve for x. whats the solutions from least to greatest. 4x^2 + 48x + 128 = 0

Respuesta :

Alfpfeu
Alfpfeu Alfpfeu
  • 01-07-2020

Answer:

[tex]\boxed{\sf \ \ \ x = -8 \ or \ x = -4 \ \ \ }[/tex]

Step-by-step explanation:

Hello,

[tex]4x^2+48x+128=0\\<=> 4(x^2+12x+32)=0\\<=> x^2+12x+32=0\\<=> (x+6)^2 - 36 + 32= 0\\\\<=> (x+6)^2-4=0\\<=> (x+6+2)(x+6-2)=0\\<=> (x+8)(x+4) = 0\\<=> x = -8 \ or \ x = -4[/tex]

Answer Link
unz unz
  • 11-01-2021

vouch, i confirm that -8, -4 are the answers

Answer Link

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