antoinestill41 antoinestill41

01-05-2020
Physics

contestada

An object moving at a velocity of 32m/s slows to a stop in 4 seconds. What was its acceleration?

Respuesta :

VirgoBoy VirgoBoy

01-05-2020

Answer:

8m/s

Explanation:

a=d/t

a=32/4

a=8 m/s

Answer Link

Chelboy Chelboy

01-05-2020

Answer:

-8m/s^2

Explanation:

initial velocity(u)=32m/s

Final velocity(v)=0

Time(t)=4seconds

Acceleration(a)=?

v=u+axt

0=32+ax4

-32=4a

a=-32/4

a=-8m/s^2

Answer Link

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