Alexisshockley
Alexisshockley Alexisshockley
  • 01-03-2020
  • Chemistry
contestada

What volume (in L) of a 2.46 M.
magnessium nitrate (Mg(NO3)2)
solution would be needed to make
275 mL of a 0.758 M solution by
dilution?

Respuesta :

Eduard22sly
Eduard22sly Eduard22sly
  • 01-03-2020

Answer:

0.0847L

Explanation:

The following data were obtained from the question:

C1 = 2.46 M

V1 =?

C2 = 0.758 M

V2 = 275 mL = 275/1000 = 0.275L

Using the dilution formula C1V1 = C2V2, we can confidently calculate the volume of the original solution as follows:

C1V1 = C2V2

2.46 x V1 = 0.758 x 0.275

Divide both side by 2.46

V1 = (0.758 x 0.275) /2.46

V1 = 0.0847L

Therefore, 0.0847L is needed

Answer Link
ndmg2005 ndmg2005
  • 30-05-2021

Answer: 0.0847

Explanation:

Answer Link

Otras preguntas

Answer this question
find the total number of combinations of 8 objects taken 5 at a time
The prospering middle class in the classical period sought aristocratic luxuries such as
What is the value of X
1.Read the dictionary entry. compound n. 1. a combination of two or more ingredients or parts 2. a substance formed by the chemical union of two or more element
Rewrite the following sentences by using direct object pronouns. Rewrite IN FRENCH. 1. Elle repasse sa jupe. ________ 2. Je ne comprends jamais le docteur. ____
if someone could answer those questions for me please that would be great!
I need help big time! Thanks for anyone who can answer this question! A company had a competition to see which team could load trucks at the loading dock the f
Why did the Chinese lose the Opium War?
Multiply the polynomials (7x2+5x+7)(4x-6)