emma1116
emma1116 emma1116
  • 03-05-2016
  • Mathematics
contestada

If the vertices of triangle bcd are b(-3,3), c(3,5), and d(-1,0), what is the perimeter

Respuesta :

apologiabiology
apologiabiology apologiabiology
  • 03-05-2016
distance formlula
D=[tex] \sqrt{(x2-x1)^{2}+(y2-y1)^{2}} [/tex]

when you want to find the distance between points (x1,y1) and (x2,y2)


we nee
distace from
b to c
c to d
d to b


b to c is (-3,3) to (3,5)
D=[tex] \sqrt{(3-(-3))^{2}+(5-3)^{2}} [/tex]=2√10

c to d is (3,5) to (-1,0)
D=[tex] \sqrt{(-1-3)^{2}+(0-5)^{2}} [/tex]=√41

d to b is (-1,0) to (-3,3)
D=[tex] \sqrt{(-3-(-1))^{2}+(3-0)^{2}} [/tex]=√13

add

b to c+c to d+d to b=2√10+√41+√13

perimiter=2√10+√41+√13 units





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