alyssa091518
alyssa091518 alyssa091518
  • 02-05-2019
  • Mathematics
contestada

The surface area of this triangular pyramid, whose base and lateral faces are congruent equilateral triangles, is __ square inches.

The surface area of this triangular pyramid whose base and lateral faces are congruent equilateral triangles is square inches class=

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calculista
calculista calculista
  • 11-05-2019

Answer:

The surface area is equal to [tex]390\ in^{2}[/tex]

Step-by-step explanation:

The surface area of the triangular pyramid is equal to the area of its four triangular faces

so

In this problem

[tex]SA=4[\frac{1}{2}(b)(h)][/tex]

we have

[tex]b=15\ in[/tex]

[tex]h=13\ in[/tex]

substitute the values

[tex]SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}[/tex]

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