huzaifakhalid7c
huzaifakhalid7c huzaifakhalid7c
  • 04-03-2016
  • Mathematics
contestada

How to solve the Quadratic Equation

12x square - 48=0

Respuesta :

Techneshaman Techneshaman
  • 04-03-2016
(To write square I will use ^2 notation here)

12x^2 - 48 = 0
Add 48 to both sides
12x^2 = 48
Divide both sides by 12
x^2 = 4
Square root both sides
x = square root of 4
x = 2 or x = -2

ANOTHER SOLUTION (edit, done later)

12x^2 - 48 = 0
divide both sides by 12
x^2 - 4 = 0
(x - 2) * (x + 2) = 0
therefore
x-2 = 0 or x+2 = 0
x = 2 or x = -2
Answer Link
isaiahmarvin1
isaiahmarvin1 isaiahmarvin1
  • 15-01-2020

Answer:  posative 4

Step-by-step explanation:

Answer Link

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