studycollabmira
studycollabmira studycollabmira
  • 03-04-2022
  • Mathematics
contestada

Raju is twice as old as Paul.
Kai is 6 years younger than Raju.
The sum of their ages is 29 years.
Form a linear equation in x and find Kai's age.​

Respuesta :

devishri1977
devishri1977 devishri1977
  • 03-04-2022
Let Paul’s age = x years
Raju’s age = 2x
To get Kai’s age, We have to subtract 6 from 2x as Kai is 6 years younger than Raju
Kai’s age = 2x -6
Sum of their ages = 29
x + 2x + 2x- 6 = 29
5x - 6 = 29

Add 6 to both sides
5x = 29 + 6
5x = 35
Dived both sides by 5
x = 35/5
x = 7
Paul’s age = 7 years
Raju’s age = 2*7
= 14 years
Kai’s age = 14 - 6
= 8 years
Answer Link

Otras preguntas

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})
What value of x makes the equation true ? 4(2x-4)=16
find the circumference of a circle whose radius is 15.4cm
What value of x makes the equation true ? 4(2x-4)=16
In scientific notation, what is the sum of 2.3 times 10^{-3} and 5.4 times 10^{-4}?a. 2.84 times 10^{-3}b. 5.63 times 10^{-3}c. 7.7 times 10^{-7}d. 12.42 times
find the circumference of a circle whose radius is 15.4cm
What value of x makes the equation true ? 4(2x-4)=16
What value of x makes the equation true ? 4(2x-4)=16
All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})
In scientific notation, what is the sum of 2.3 times 10^{-3} and 5.4 times 10^{-4}?a. 2.84 times 10^{-3}b. 5.63 times 10^{-3}c. 7.7 times 10^{-7}d. 12.42 times